25x(^2)-125=0

Solution for 25x(^2)-125=0 equation:

25x(^2)-125=0

a = 25; b = 0; c = -125;
Δ = b2-4ac
Δ = 02-4·25·(-125)
Δ = 12500
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{12500}=\sqrt{2500*5}=\sqrt{2500}*\sqrt{5}=50\sqrt{5}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-50\sqrt{5}}{2*25}=\frac{0-50\sqrt{5}}{50}
=-\frac{50\sqrt{5}}{50}
=-\sqrt{5}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+50\sqrt{5}}{2*25}=\frac{0+50\sqrt{5}}{50}
=\frac{50\sqrt{5}}{50}
=\sqrt{5}
$